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@@ -76,7 +76,7 @@ independent aggregation of the stakes, meaning the property of a leader winning
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$1-\phi(\sum_{i}\sigma_i)=1-(1+(1-f)^{\sigma_i})=-(1-f)^{\sum_{i}\sigma_i}$,
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$1-\phi(\sum_{i}\sigma_i)=1-(1+(1-f)^{\sigma_i})=-(1-f)^{\sum_{i}\sigma_i}$,
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the joint "one minus probability" of all the stakes (each with probability $\phi(\sigma_i))$
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the joint "one minus probability" of all the stakes (each with probability $\phi(\sigma_i))$
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winning aggregated winning the leadership
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winning aggregated winning the leadership
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-$\prod_{i}^{n}(1-\phi(\sigma_i))=-(1-f)^{\sum_{\sigma_i}}$
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+$\prod_{i}^{n}(1-\phi(\sigma_i))=-(1-f)^{\sum_i(\sigma_i)}$
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thus:
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thus:
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$$ 1-\phi(\sum_{i}\sigma_i) =\prod_{i}^{n}(1-\phi(\sigma_i)) $$
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$$ 1-\phi(\sum_{i}\sigma_i) =\prod_{i}^{n}(1-\phi(\sigma_i)) $$
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@@ -104,7 +104,8 @@ note that $(\frac{1}{v_{max}})^{n-1} < 1, V>1$, thus competing with single coin
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$$y<2^{\frac{l}{v}}\Sigma$$ for example for a group order or l=24 bits, and maximum value of $v_{max}=2^{10}$, then lead statement:
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$$y<2^{\frac{l}{v}}\Sigma$$ for example for a group order or l=24 bits, and maximum value of $v_{max}=2^{10}$, then lead statement:
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$$y<2^{14}\Sigma$$
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$$y<2^{14}\Sigma$$
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-
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+### pairing leader selection independent aggregation function
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+TODO
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## Leaky non-resettable beacon
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## Leaky non-resettable beacon
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