|
|
@@ -0,0 +1,68 @@
|
|
|
+from tabulate import tabulate
|
|
|
+# This is a more usable version of valuate.sage, less instructional
|
|
|
+
|
|
|
+K.<x, y> = GF(11)[]
|
|
|
+Px, Py = K(2), K(4)
|
|
|
+S = K.quotient(y^2 - x^3 - 4*x).fraction_field()
|
|
|
+X, Y = S(x), S(y)
|
|
|
+
|
|
|
+EC_A = 4
|
|
|
+EC_B = 0
|
|
|
+EC = y^2 - x^3 - EC_A*x - EC_B
|
|
|
+
|
|
|
+original_f = (y - 2*x)^2
|
|
|
+b0, b1, b2 = [(x - Px), (y - Py), 1]
|
|
|
+
|
|
|
+# Return components for basis
|
|
|
+def decomp(f):
|
|
|
+ a0, r = f.quo_rem(b0)
|
|
|
+ a1, r = r.quo_rem(b1)
|
|
|
+ a2, r = r.quo_rem(b2)
|
|
|
+ assert r == 0
|
|
|
+ return [a0, a1, a2]
|
|
|
+
|
|
|
+def comp(comps):
|
|
|
+ return sum(a*b for a, b in zip(comps, (b0, b1, b2)))
|
|
|
+
|
|
|
+assert comp(decomp(original_f)) == original_f
|
|
|
+
|
|
|
+# so we can replace (y - Py) with this
|
|
|
+Ef = b0^2 + binomial(3,2)*Px*b0^1 + (3*Px^2 + EC_A)
|
|
|
+Eg = (y + Py)
|
|
|
+assert EC == b1*Eg - b0*Ef
|
|
|
+
|
|
|
+def apply_reduction(a, g):
|
|
|
+ assert a[2] == 0
|
|
|
+ a[0] = a[0]*Eg + a[1]*Ef
|
|
|
+ a[1] = 0
|
|
|
+ g[0] *= Eg
|
|
|
+
|
|
|
+k = 0
|
|
|
+a = [original_f, 0, 0]
|
|
|
+g = [1]
|
|
|
+
|
|
|
+table = []
|
|
|
+table.append(("", "a", "g", "k"))
|
|
|
+
|
|
|
+def log(step_name, a, g, k):
|
|
|
+ table.append((step_name, str(a), str(g), k))
|
|
|
+
|
|
|
+log("start", a, g, k)
|
|
|
+
|
|
|
+while True:
|
|
|
+ f = a[0]
|
|
|
+ a = decomp(f)
|
|
|
+ log("decomp", a, g, k)
|
|
|
+
|
|
|
+ # Check remainder
|
|
|
+ if a[2] != 0:
|
|
|
+ break
|
|
|
+
|
|
|
+ # We can apply a reduction
|
|
|
+ k += 1
|
|
|
+
|
|
|
+ apply_reduction(a, g)
|
|
|
+ log("reduce", a, g, k)
|
|
|
+
|
|
|
+print(tabulate(table))
|
|
|
+print(f"k = {k}")
|