plonk.sage 11 KB

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  1. q = 0x40000000000000000000000000000000224698fc0994a8dd8c46eb2100000001
  2. K = GF(q)
  3. P.<X> = K[]
  4. # The pallas and vesta curves are 2-adic. This means there is a large
  5. # power of 2 subgroup within both of their fields.
  6. # This function finds a generator for this subgroup within the field.
  7. def get_omega():
  8. # Slower alternative:
  9. # generator = K.multiplicative_generator()
  10. # Just hardcode the value here instead
  11. generator = K(5)
  12. assert (q - 1) % 2^32 == 0
  13. # Root of unity
  14. t = (q - 1) / 2^32
  15. omega = generator**t
  16. assert omega != 1
  17. assert omega^(2^16) != 1
  18. assert omega^(2^31) != 1
  19. assert omega^(2^32) == 1
  20. return omega
  21. # Order of this element is 2^32
  22. omega = get_omega()
  23. # f(s, x, y) = sxy + (1 - s)(x + y)
  24. var_one = K(1)
  25. var_x = K(4)
  26. var_y = K(6)
  27. var_s = K(1)
  28. var_xy = var_x * var_y
  29. var_x_y = var_x + var_y
  30. var_1_neg_s = var_one - var_s
  31. var_sxy = var_s * var_xy
  32. var_1_neg_s_x_y = var_1_neg_s * var_x_y
  33. #var_s_neg_1 = -var_1_neg_s
  34. var_zero = K(0)
  35. public_value = -(var_s * (var_x * var_y) + (1 - var_s) * (var_x + var_y))
  36. # Ql a + Qr b + Qm a b + Qo c + Qc + P == 0
  37. # See also the file plonk-naive.sage
  38. # x * y = xy
  39. a1, b1, c1 = var_x, var_y, var_xy
  40. Ql1, Qr1, Qm1, Qo1, Qc1 = 0, 0, 1, -1, 0
  41. assert Ql1 * a1 + Qr1 * b1 + Qm1 * a1 * b1 + Qo1 * c1 + Qc1 == 0
  42. # x + y = (x + y)
  43. a2, b2, c2 = var_x, var_y, var_x_y
  44. Ql2, Qr2, Qm2, Qo2, Qc2 = 1, 1, 0, -1, 0
  45. assert Ql2 * a2 + Qr2 * b2 + Qm2 * a2 * b2 + Qo2 * c2 + Qc2 == 0
  46. # 1 - s = (1 - s)
  47. a3, b3, c3 = var_one, var_s, var_1_neg_s
  48. Ql3, Qr3, Qm3, Qo3, Qc3 = 1, -1, 0, -1, 0
  49. assert Ql3 * a3 + Qr3 * b3 + Qm3 * a3 * b3 + Qo3 * c3 + Qc3 == 0
  50. # s * (xy) = sxy
  51. a4, b4, c4 = var_s, var_xy, var_sxy
  52. Ql4, Qr4, Qm4, Qo4, Qc4 = 0, 0, 1, -1, 0
  53. assert Ql4 * a4 + Qr4 * b4 + Qm4 * a4 * b4 + Qo4 * c4 + Qc4 == 0
  54. # (1 - s) * (x + y) = [(1 - s)(x + y)]
  55. a5, b5, c5 = var_1_neg_s, var_x_y, var_1_neg_s_x_y
  56. Ql5, Qr5, Qm5, Qo5, Qc5 = 0, 0, 1, -1, 0
  57. assert Ql5 * a5 + Qr5 * b5 + Qm5 * a5 * b5 + Qo5 * c5 + Qc5 == 0
  58. # (sxy) + [(1 - s)(x + y)] = public_value
  59. # c6 is unused
  60. a6, b6, c6 = var_sxy, var_1_neg_s_x_y, var_zero
  61. Ql6, Qr6, Qm6, Qo6, Qc6 = 1, 1, 0, 0, 0
  62. assert Ql6 * a6 + Qr6 * b6 + Qm6 * a6 * b6 + Qo6 * c6 + Qc6 + public_value == 0
  63. # one == 1, b7 and c7 unused
  64. a7, b7, c7 = var_one, var_zero, var_zero
  65. Ql7, Qr7, Qm7, Qo7, Qc7 = 1, 0, 0, 0, -1
  66. assert Ql7 * a7 + Qr7 * b7 + Qm7 * a7 * b7 + Qo7 * c7 + Qc7 == 0
  67. # Add a last fake constraint so n is a power of 2
  68. # This is needed since we are working with omega whose size is 2^32
  69. # and we will create a generator from it whose order is 2^3
  70. a8, b8, c8 = var_zero, var_zero, var_zero
  71. Ql8, Qr8, Qm8, Qo8, Qc8 = 0, 0, 0, 0, 0
  72. assert Ql8 * a8 + Qr8 * b8 + Qm8 * a8 * b8 + Qo8 * c8 + Qc8 == 0
  73. a = [a1, a2, a3, a4, a5, a6, a7, a8]
  74. b = [b1, b2, b3, b4, b5, b6, b7, b8]
  75. c = [c1, c2, c3, c4, c5, c6, c7, c8]
  76. Ql = [Ql1, Ql2, Ql3, Ql4, Ql5, Ql6, Ql7, Ql8]
  77. Qr = [Qr1, Qr2, Qr3, Qr4, Qr5, Qr6, Qr7, Qr8]
  78. Qm = [Qm1, Qm2, Qm3, Qm4, Qm5, Qm6, Qm7, Qm8]
  79. Qo = [Qo1, Qo2, Qo3, Qo4, Qo5, Qo6, Qo7, Qo8]
  80. Qc = [Qc1, Qc2, Qc3, Qc4, Qc5, Qc6, Qc7, Qc8]
  81. public_values = [0, 0, 0, 0, 0, public_value, 0, 0]
  82. n = 8
  83. for a_i, b_i, c_i, Ql_i, Qr_i, Qm_i, Qo_i, Qc_i, public_i in \
  84. zip(a, b, c, Ql, Qr, Qm, Qo, Qc, public_values):
  85. assert (Ql_i * a_i + Qr_i * b_i + Qm_i * a_i * b_i + Qo_i * c_i
  86. + Qc_i + public_i) == 0
  87. # 0 1 2 3 4 5 6 7
  88. # a: x, x, 1, s, 1 - s, sxy, 1 -
  89. #
  90. # 8 9 10 11 12 13 14 15
  91. # b: y, y, s, xy, x + y, (1 - s)(x + y), - -
  92. #
  93. # 16 17 18 19 20 21 22 23
  94. # c: xy, x + y, 1 - s, sxy, (1 - s)(x + y), -, - -
  95. permuted_indices_a = [1, 0, 6, 10, 18, 19, 2, 7]
  96. permuted_indices_b = [8, 9, 3, 16, 17, 20, 14, 15]
  97. permuted_indices_c = [11, 12, 4, 5, 13, 21, 22, 23]
  98. eval_domain = range(0, n * 3)
  99. witness = a + b + c
  100. permuted_indices = permuted_indices_a + permuted_indices_b + permuted_indices_c
  101. for i, val in enumerate(a + b + c):
  102. assert val == witness[permuted_indices[i]]
  103. omega = omega^(2^32 / n)
  104. assert omega^n == 1
  105. # Calculate the vanishing polynomial
  106. # This is the same as (X - omega^0)(X - omega^1)...(X - omega^{n - 1})
  107. Z_H = X^n - 1
  108. assert Z_H(1) == 0
  109. assert Z_H(omega^4) == 0
  110. qL_X = P.lagrange_polynomial((omega^i, Ql_i) for i, Ql_i in enumerate(Ql))
  111. qR_X = P.lagrange_polynomial((omega^i, Qr_i) for i, Qr_i in enumerate(Qr))
  112. qM_X = P.lagrange_polynomial((omega^i, Qm_i) for i, Qm_i in enumerate(Qm))
  113. qO_X = P.lagrange_polynomial((omega^i, Qo_i) for i, Qo_i in enumerate(Qo))
  114. qC_X = P.lagrange_polynomial((omega^i, Qc_i) for i, Qc_i in enumerate(Qc))
  115. PI_X = P.lagrange_polynomial((omega^i, public_i) for i, public_i
  116. in enumerate(public_values))
  117. b_1 = K.random_element()
  118. b_2 = K.random_element()
  119. b_3 = K.random_element()
  120. b_4 = K.random_element()
  121. b_5 = K.random_element()
  122. b_6 = K.random_element()
  123. b_7 = K.random_element()
  124. b_8 = K.random_element()
  125. b_9 = K.random_element()
  126. # Round 1
  127. # Calculate wire witness polynomials
  128. a_X = (b_1 * X + b_2) * Z_H + \
  129. P.lagrange_polynomial((omega^i, a_i) for i, a_i in enumerate(a))
  130. assert a_X(omega^2) == a[2]
  131. b_X = (b_3 * X + b_4) * Z_H + \
  132. P.lagrange_polynomial((omega^i, b_i) for i, b_i in enumerate(b))
  133. assert b_X(omega^5) == b[5]
  134. c_X = (b_5 * X + b_6) * Z_H + \
  135. P.lagrange_polynomial((omega^i, c_i) for i, c_i in enumerate(c))
  136. assert c_X(omega^0) == c[0]
  137. # Commit to a(X), b(X), c(X)
  138. # ...
  139. # Round 2
  140. beta = K.random_element()
  141. gamma = K.random_element()
  142. def find_quadratic_non_residue():
  143. k = K.random_element()
  144. while kronecker(k, q) != -1:
  145. k = K.random_element()
  146. return k
  147. # These values do not have a square root
  148. k1 = find_quadratic_non_residue()
  149. k2 = find_quadratic_non_residue()
  150. assert k1 != k2
  151. indices = ([omega^i for i in range(n)]
  152. + [k1 * omega^i for i in range(n)]
  153. + [k2 * omega^i for i in range(n)])
  154. # Permuted indices
  155. sigma_star = [indices[i] for i in permuted_indices]
  156. permutation_points = [(1, 1)]
  157. for i in range(n - 1):
  158. x = omega^(i + 1)
  159. y = 1
  160. for j in range(i + 1):
  161. y *= witness[j] + beta * omega^j + gamma
  162. y *= witness[n + j] + beta * k1 * omega^j + gamma
  163. y *= witness[2 * n + j] + beta * k2 * omega^j + gamma
  164. y /= witness[j] + sigma_star[j] * beta + gamma
  165. y /= witness[n + j] + sigma_star[n + j] * beta + gamma
  166. y /= witness[2 * n + j] + sigma_star[2 * n + j] * beta + gamma
  167. permutation_points.append((x, y))
  168. z_X = (b_7 * X^2 + b_8 * X + b_9) * Z_H + \
  169. P.lagrange_polynomial(permutation_points)
  170. assert witness[0] == 4
  171. assert witness[n] == 6
  172. assert witness[2 * n] == var_xy == 24
  173. assert sigma_star[0] == omega
  174. assert sigma_star[n] == k1 * omega^8
  175. assert sigma_star[2 * n] == k1 * omega^11
  176. assert z_X(omega^0) == 1
  177. assert ((4 + beta + gamma) * (6 + beta * k1 + gamma) * (24 + beta * k2 + gamma)
  178. ) == (z_X(omega)
  179. * (4 + omega * beta + gamma)
  180. * (6 + k1 * omega^8 * beta + gamma)
  181. * (24 + k1 * omega^11 * beta + gamma))
  182. assert witness[2] == var_one == 1
  183. assert witness[n + 2] == var_s == 1
  184. assert witness[2 * n + 2] == var_1_neg_s == 0
  185. assert sigma_star[2] == omega^6
  186. assert sigma_star[n + 2] == omega^3
  187. assert sigma_star[2 * n + 2] == omega^4
  188. assert (z_X(omega^2) * (1 + beta * omega^2 + gamma)
  189. * (1 + beta * k1 * omega^2 + gamma)
  190. * (0 + beta * k2 * omega^2 + gamma)
  191. ) == (z_X(omega^3) * (1 + omega^6 * beta + gamma)
  192. * (1 + omega^3 * beta + gamma)
  193. * (0 + omega^4 * beta + gamma))
  194. # Round 3
  195. alpha = K.random_element()
  196. Ssigma_1 = P.lagrange_polynomial((omega^i, sigma_star[i]) for i in range(8))
  197. Ssigma_2 = P.lagrange_polynomial((omega^i, sigma_star[n + i]) for i in range(8))
  198. Ssigma_3 = P.lagrange_polynomial((omega^i, sigma_star[2 * n + i])
  199. for i in range(8))
  200. assert Ssigma_1(omega^0) == omega^1
  201. assert Ssigma_1(omega^3) == k1 * omega^10
  202. assert Ssigma_2(omega^2) == omega^3
  203. assert Ssigma_3(omega^7) == k2 * omega^7 == k2 * omega^23
  204. t_X_constraints = ((a_X * b_X * qM_X) + (a_X * qL_X) + (b_X * qR_X)
  205. + (c_X * qO_X) + qC_X + PI_X)
  206. for i in range(8):
  207. assert t_X_constraints(omega^i) == 0
  208. t_X_permutations = ((a_X + beta * X + gamma)
  209. * (b_X + beta * k1 * X + gamma)
  210. * (c_X + beta * k2 * X + gamma) * z_X
  211. # Permutated accumulator
  212. - (a_X + beta * Ssigma_1 + gamma)
  213. * (b_X + beta * Ssigma_2 + gamma)
  214. * (c_X + beta * Ssigma_3 + gamma) * z_X(X * omega))
  215. for i in range(8):
  216. assert t_X_permutations(omega^i) == 0
  217. L1_X = P.lagrange_polynomial([(1, 1)] + [(omega^i, 0) for i in range(1, n)])
  218. assert L1_X(omega^0) == 1
  219. assert L1_X(omega^2) == 0
  220. t_X_zloops = (z_X - 1) * L1_X
  221. assert t_X_zloops(omega^0) == 0
  222. assert t_X_zloops(omega^2) == 0
  223. assert t_X_zloops(omega^8) == 0
  224. t = (t_X_constraints + t_X_permutations * alpha + t_X_zloops * alpha^2) / Z_H
  225. # Commit to t
  226. # ...
  227. # Round 4
  228. zeta = K.random_element()
  229. a_bar = a_X(zeta)
  230. b_bar = b_X(zeta)
  231. c_bar = c_X(zeta)
  232. s_bar_1 = Ssigma_1(zeta)
  233. s_bar_2 = Ssigma_2(zeta)
  234. z_bar_omega = z_X(zeta * omega)
  235. # Now we provide proofs that all the above values are correct openings
  236. # of the committed polynomials.
  237. # And we prove that a reconstructed version of t(X) from the polynomial
  238. # commitments of the witness and permutation polynomials equals the
  239. # t(X) commitment.
  240. # t(X) - r(X) = 0 where r(X) is the reconstructed polynomial.
  241. # In order to avoid sending Ssigma_1(zeta) and z(zeta), plonk does an
  242. # optimization using the Maller trick documented in section 4 under
  243. # the title "Reducing the number of field elements"
  244. # Round 5
  245. # To reduce the proof by two elements, we construct a linearization polynomial
  246. # which only contains 1 interminate per multiplication expression which is
  247. # enough to prove the polynomial correctly evaluates.
  248. r = (
  249. # This is proving the constraint polynomial has roots at H
  250. (a_bar * b_bar * qM_X) + (a_bar * qL_X) + (b_bar * qR_X)
  251. + (c_bar * qO_X) + PI_X + qC_X
  252. + alpha * ((a_bar + beta * zeta + gamma)
  253. * (b_bar + beta * k1 * zeta + gamma)
  254. * (c_bar + beta * k2 * zeta + gamma) * z_X
  255. -
  256. (a_bar + beta * s_bar_1 + gamma)
  257. * (b_bar + beta * s_bar_2 + gamma)
  258. * (c_bar + beta * Ssigma_3 + gamma) * z_bar_omega)
  259. + alpha^2 * (z_X - 1) * L1_X(zeta)
  260. # t = (t_X_constraints + t_X_permutations * alpha + t_X_zloops * alpha^2)
  261. # -------------------------------------------------------------------
  262. # Z_H
  263. - Z_H(zeta) * t
  264. )
  265. assert r(zeta) == 0
  266. # That is basically the plonk prover. The remaining stuff are details such as
  267. # which polynomial commitment scheme you use (kate, bulletproofs, ...)