halo2.sage 10 KB

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  1. import numpy as np
  2. q = 0x40000000000000000000000000000000224698fc0994a8dd8c46eb2100000001
  3. K = GF(q)
  4. P.<X> = K[]
  5. # GENERATOR^{2^s} where t * 2^s + 1 = q with t odd.
  6. # In other words, this is a t root of unity.
  7. generator = K(5)
  8. # There is a large 2^32 order subgroup in this curve because it is 2-adic
  9. t = (K(q) - 1) / 2^32
  10. assert int(t) % 2 != 0
  11. delta = generator^(2^32)
  12. assert delta^t == 1
  13. # The size of the multiplicative group is phi(q) = q - 1
  14. # And inside this group are 2 distinct subgroups of size t and 2^s.
  15. # delta is the generator for the size t subgroup, and omega for the 2^s one.
  16. # Taking powers of these generators and multiplying them will produce
  17. # unique cosets that divide the entire group for q.
  18. def get_omega():
  19. generator = K(5)
  20. assert (q - 1) % 2^32 == 0
  21. # Root of unity
  22. t = (q - 1) / 2^32
  23. omega = generator**t
  24. assert omega != 1
  25. assert omega^(2^16) != 1
  26. assert omega^(2^31) != 1
  27. assert omega^(2^32) == 1
  28. return omega
  29. # Order of this element is 2^32
  30. omega = get_omega()
  31. k = 4
  32. n = 2^k
  33. omega = omega^(2^32 / n)
  34. assert omega^n == 1
  35. # Arithmetization for:
  36. # sxy + (s - 1)(x + y) - z = 0
  37. # s(s - 1) = 0
  38. # F1(A1 - 1) + F2 (A1 - I) + F3((1 - A1)(A2 + A3) - A4) + F4(A1 A2 A3 - A4) = 0
  39. A = []
  40. F = []
  41. var_zero = K(0)
  42. var_x = K(4)
  43. var_y = K(6)
  44. var_s = K(1)
  45. var_sxy = var_s * var_x * var_y
  46. var_1s_xy = (1 - var_s) * (var_x + var_y)
  47. # Public
  48. var_z = var_sxy + var_1s_xy
  49. # 4 advice columns
  50. # 4 fixed columns
  51. # 1 instance column
  52. # Row 1
  53. # z = public z
  54. A_1_1, A_2_1, A_3_1, A_4_1 = var_z, 0, 0, 0
  55. F_1_1, F_2_1, F_3_1, F_4_1 = 1, 0, 0, 0
  56. I_1 = var_z
  57. # Row 2
  58. # ~0 == 0
  59. A_1_2, A_2_2, A_3_2, A_4_2 = var_zero, 0, 0, 0
  60. F_1_2, F_2_2, F_3_2, F_4_2 = 0, 1, 0, 0
  61. I_2 = 0
  62. # Row 3
  63. # Boolean check
  64. # (1 - s)(s + 0) == 0
  65. A_1_3, A_2_3, A_3_3, A_4_3 = var_s, var_s, var_zero, var_zero
  66. F_1_3, F_2_3, F_3_3, F_4_3 = 0, 0, 1, 0
  67. I_3 = 0
  68. # Row 4
  69. # s x y == sxy
  70. A_1_4, A_2_4, A_3_4, A_4_4 = var_s, var_x, var_y, var_sxy
  71. F_1_4, F_2_4, F_3_4, F_4_4 = 0, 0, 0, 1
  72. I_4 = 0
  73. # Row 5
  74. # (1 - s)(x + y) = (1-s)(x+y)
  75. A_1_5, A_2_5, A_3_5, A_4_5 = var_s, var_x, var_y, var_1s_xy
  76. F_1_5, F_2_5, F_3_5, F_4_5 = 0, 0, 1, 0
  77. I_5 = 0
  78. # Row 6
  79. # (1 - 0)(sxy + (1-s)(x+y)) = z
  80. A_1_6, A_2_6, A_3_6, A_4_6 = var_zero, var_sxy, var_1s_xy, var_z
  81. F_1_6, F_2_6, F_3_6, F_4_6 = 0, 0, 1, 0
  82. I_6 = 0
  83. A1 = [A_1_1, A_1_2, A_1_3, A_1_4, A_1_5, A_1_6]
  84. A2 = [A_2_1, A_2_2, A_2_3, A_2_4, A_2_5, A_2_6]
  85. A3 = [A_3_1, A_3_2, A_3_3, A_3_4, A_3_5, A_3_6]
  86. A4 = [A_4_1, A_4_2, A_4_3, A_4_4, A_4_5, A_4_6]
  87. F1 = [F_1_1, F_1_2, F_1_3, F_1_4, F_1_5, F_1_6]
  88. F2 = [F_2_1, F_2_2, F_2_3, F_2_4, F_2_5, F_2_6]
  89. F3 = [F_3_1, F_3_2, F_3_3, F_3_4, F_3_5, F_3_6]
  90. F4 = [F_4_1, F_4_2, F_4_3, F_4_4, F_4_5, F_4_6]
  91. I = [I_1, I_2, I_3, I_4, I_5, I_6]
  92. # There should be 5 unused blinding rows.
  93. # see src/plonk/circuit.rs: fn blinding_factors(&self) -> usize;
  94. # We have 9 so we are perfectly fine.
  95. # Add 9 empty rows
  96. assert n - len(A1) == 10
  97. for i in range(10):
  98. A1.append(K.random_element())
  99. A2.append(K.random_element())
  100. A3.append(K.random_element())
  101. A4.append(K.random_element())
  102. F1.append(0)
  103. F2.append(0)
  104. F3.append(0)
  105. F4.append(0)
  106. I.append(K.random_element())
  107. assert (len(A1) == len(A2) == len(A3) == len(A4) == len(F1) == len(F2)
  108. == len(F3) == len(F4) == len(I) == n)
  109. for A_1_i, A_2_i, A_3_i, A_4_i, F_1_i, F_2_i, F_3_i, F_4_i, I_i in zip(
  110. A1, A2, A3, A4, F1, F2, F3, F4, I):
  111. assert (F_1_i * (A_1_i - I_i)
  112. + F_2_i * A_1_i
  113. + F_3_i * ((1 - A_1_i) * (A_2_i + A_3_i) - A_4_i)
  114. + F_4_i * (A_1_i * A_2_i * A_3_i - A_4_i)) == 0
  115. a_1_X = P.lagrange_polynomial((omega^i, A_1_i) for i, A_1_i in enumerate(A1))
  116. a_2_X = P.lagrange_polynomial((omega^i, A_2_i) for i, A_2_i in enumerate(A2))
  117. a_3_X = P.lagrange_polynomial((omega^i, A_3_i) for i, A_3_i in enumerate(A3))
  118. a_4_X = P.lagrange_polynomial((omega^i, A_4_i) for i, A_4_i in enumerate(A4))
  119. f_1_X = P.lagrange_polynomial((omega^i, F_1_i) for i, F_1_i in enumerate(F1))
  120. f_2_X = P.lagrange_polynomial((omega^i, F_2_i) for i, F_2_i in enumerate(F2))
  121. f_3_X = P.lagrange_polynomial((omega^i, F_3_i) for i, F_3_i in enumerate(F3))
  122. f_4_X = P.lagrange_polynomial((omega^i, F_4_i) for i, F_4_i in enumerate(F4))
  123. # Treat the instance wire as a 5th advice wire
  124. a_5_X = P.lagrange_polynomial((omega^i, A_5_i) for i, A_5_i in enumerate(I))
  125. for i, (A_1_i, A_2_i, A_3_i, A_4_i, F_1_i, F_2_i, F_3_i, F_4_i, I_i) in \
  126. enumerate(zip(A1, A2, A3, A4, F1, F2, F3, F4, I)):
  127. assert a_1_X(omega^i) == A_1_i
  128. assert a_2_X(omega^i) == A_2_i
  129. assert a_3_X(omega^i) == A_3_i
  130. assert a_4_X(omega^i) == A_4_i
  131. assert a_5_X(omega^i) == I_i
  132. assert f_1_X(omega^i) == F_1_i
  133. assert f_2_X(omega^i) == F_2_i
  134. assert f_3_X(omega^i) == F_3_i
  135. assert f_4_X(omega^i) == F_4_i
  136. # beta, gamma
  137. beta = K.random_element()
  138. gamma = K.random_element()
  139. # 0 1 2 3 4 5 ... 15
  140. # A1: z, 0, s, s, s, 0,
  141. #
  142. # 16 17 18 19 20 21 ... 31
  143. # A2: -, -, s, x, x, sxy,
  144. #
  145. # 32 33 34 35 36 37 ... 47
  146. # A3: -, -, 0, y, y, (1-s)(x+y),
  147. #
  148. # 48 49 50 51 52 53 ... 63
  149. # A4: -, -, 0, sxy, (1-s)(x + y), z,
  150. #
  151. # 64 65 66 67 68 69 ... 79
  152. # A5: z, -, -, -, -, -,
  153. # z = (0 53 64)
  154. # 0 = (1 5 34 50)
  155. # s = (2 3 4 18)
  156. # x = (19 20)
  157. # sxy = (21 51)
  158. # y = (35 36)
  159. # (1-s)(x+y) = (37 52)
  160. permuted_indices = list(range(n * 5))
  161. assert len(permuted_indices) == 80
  162. # Apply the actual permutation cycles
  163. # z
  164. permuted_indices[0] = 53
  165. permuted_indices[53] = 64
  166. permuted_indices[64] = 0
  167. # ~0
  168. permuted_indices[1] = 5
  169. permuted_indices[5] = 34
  170. permuted_indices[34] = 50
  171. permuted_indices[50] = 1
  172. # s
  173. permuted_indices[2] = 3
  174. permuted_indices[3] = 4
  175. permuted_indices[4] = 18
  176. permuted_indices[18] = 2
  177. # x
  178. permuted_indices[19] = 20
  179. permuted_indices[20] = 19
  180. # sxy
  181. permuted_indices[21] = 51
  182. permuted_indices[51] = 21
  183. # y
  184. permuted_indices[35] = 36
  185. permuted_indices[36] = 35
  186. # (1-s)(x+y)
  187. permuted_indices[37] = 52
  188. permuted_indices[52] = 37
  189. witness = A1 + A2 + A3 + A4 + I
  190. for i, val in enumerate(witness):
  191. assert val == witness[permuted_indices[i]]
  192. # How to join lists together?
  193. indices = ([omega^i for i in range(n)]
  194. + [delta * omega^i for i in range(n)]
  195. + [delta^2 * omega^i for i in range(n)]
  196. + [delta^3 * omega^i for i in range(n)]
  197. + [delta^4 * omega^i for i in range(n)])
  198. assert len(indices) == 80
  199. # Permuted indices
  200. sigma_star = [indices[i] for i in permuted_indices]
  201. s = [sigma_star[:n], sigma_star[n:2 * n], sigma_star[2 * n:3 * n],
  202. sigma_star[3 * n:4 * n], sigma_star[4 * n:]]
  203. assert s[0] + s[1] + s[2] + s[3] + s[4] == sigma_star
  204. v = [A1, A2, A3, A4, I]
  205. # We split the columns into sets of size m.
  206. # Here we will use m = 1 for illustration purposes
  207. # We have 6 usable rows
  208. # n = 16 rows total
  209. # row u (q_last) will be the 7th row
  210. # So we have 9 unusable rows
  211. q_blind = [0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1]
  212. q_last = [0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0]
  213. # Turn both of these into polynomial form
  214. q_blind = P.lagrange_polynomial((omega^i, q_i) for i, q_i in enumerate(q_blind))
  215. assert q_blind(omega^5) == 0
  216. assert q_blind(omega^6) == 0
  217. assert q_blind(omega^7) == 1
  218. assert q_blind(omega^11) == 1
  219. q_last = P.lagrange_polynomial((omega^i, q_i) for i, q_i in enumerate(q_last))
  220. assert q_last(omega^5) == 0
  221. assert q_last(omega^6) == 1
  222. assert q_last(omega^7) == 0
  223. assert q_last(omega^11) == 0
  224. m = 5
  225. assert n == 16
  226. # 6 usable rows
  227. u = 6
  228. # There are 5 columns
  229. # We will split the columns partitions into 5 partitions to make things easy
  230. # So b = 5, and each partition contains only a single column
  231. # We still iterate over the column to make it more obvious
  232. m = 1
  233. permutation_points = [(1, 1)]
  234. last_y_value = 1
  235. ZP = []
  236. # a is the current column partition we are aggregating
  237. for a in range(5):
  238. # j iterates over the rows
  239. for j in range(u):
  240. current = last_y_value
  241. # i iterates over the columns in our partition
  242. for i in range(a * m, (a + 1)):
  243. current *= v[i][j] + beta * delta^i * omega^j + gamma
  244. current /= v[i][j] + beta * s[i][j] + gamma
  245. last_y_value = current
  246. permutation_points.append((omega^(j + 1), current))
  247. ZP_a = P.lagrange_polynomial(permutation_points)
  248. ZP.append(ZP_a)
  249. permutation_points = [(1, last_y_value)]
  250. # l_0(X) (1 - ZP,0(X)) = 0
  251. # => ZP,0(1) = 1
  252. assert ZP[0](1) == 1
  253. # Checks for l_0(X) (ZP,a(X) - ZP,a-1(omega^u X)) = 1
  254. # => ZP,a(Z) = ZP,a-1(omega^u X)
  255. # This copies the end value from one partition to the next one
  256. assert ZP[1](omega^0) == ZP[0](omega^u)
  257. assert ZP[2](omega^0) == ZP[1](omega^u)
  258. assert ZP[3](omega^0) == ZP[2](omega^u)
  259. assert ZP[4](omega^0) == ZP[3](omega^u)
  260. # Allow the last value to be either 0 or 1 for full ZK
  261. assert ZP[4](omega^u) in (0, 1)
  262. y = K.random_element()
  263. gate_0 = f_1_X * (a_1_X - a_5_X)
  264. gate_1 = f_2_X * a_1_X
  265. gate_2 = f_3_X * ((1 - a_1_X) * (a_2_X + a_3_X) - a_4_X)
  266. gate_3 = f_4_X * (a_1_X * a_2_X * a_3_X - a_4_X)
  267. c = gate_0 + y * gate_1 + y^2 * gate_2 + y^3 * gate_3
  268. t = X^n - 1
  269. for i in range(n):
  270. assert h(omega^i) == 0
  271. # Normally we do:
  272. #h = c / t
  273. # But for some reason sage is producing fractional coefficients
  274. h, rem = c.quo_rem(t)
  275. assert rem == 0
  276. # We send commitments to the terms of h(X)
  277. # h_0(x), ..., h_{d - 1}(x)
  278. # Commitments:
  279. # H = [H_0, ..., H_{d - 1}]
  280. x = K.random_element()
  281. # Send evaluations at x of everything we committed to so far
  282. # A_0(x), ..., A_{m - 1}(x)
  283. # ZP,0(x), ..., ZP,b-1(x)
  284. # H_0(x), ..., H_{d-1}(x)
  285. a_evals = [a_1_X(x), a_2_X(x), a_3_X(x), a_4_X(x), a_5_X(x)]
  286. h_evals = []
  287. # Iterate starting from lowest powers first
  288. h_test = 0
  289. for i, h_i in enumerate(h):
  290. h_evals.append(h_i * x^i)
  291. h_test += h_i * X^i
  292. assert h_test == h
  293. assert sum(h_evals) == h(x)
  294. assert sum(h_evals) * t(x) == (
  295. f_1_X(x) * (a_evals[0] - a_evals[4])
  296. + y * f_2_X(x) * a_evals[0]
  297. + y^2 * f_3_X(x) * ((1 - a_evals[0]) * (a_evals[1] + a_evals[2])
  298. - a_evals[3])
  299. + y^3 * f_4_X(x) * (a_evals[0] * a_evals[1] * a_evals[2] - a_evals[3]))