q = 19 Fq = GF(q) E = EllipticCurve(Fq, [0, 5]) assert q % 3 == 1 xi3 = Fq(7) assert xi3^3 == 1 P = E(-1, 2) print(f"xi(P) = {E(xi3 * -1, 2)}") Fq.<x> = GF(23)[] Fq2.<u> = Fq.extension(x^2 + 1) E = EllipticCurve(Fq2, [0, 5]) P = E(-1, 2) xi3 = 8 * u + 11 print(f"xi(P) = {E(-xi3, 2)}")
